Question 702392: I was given the word problem:
While Darnell is grounded his friend Jack brings him a video game. Darnell stands at his bedroom window, and Jack stands directly below the window. If Jack tosses a game cartridge to Darnell with an initial velocity of 35 feet per second, an equation for the height h feet of the cartridge after t seconds is h=-16t^2+35t+5.
a. If the window is 25 feet above the ground, will Darnell have 0, 1, or 2 chances to catch the video game?
b. If Darnell is unable to catch the video game, when will it hit the ground?
Can you please help, I'm lost.
Thank you!
Found 2 solutions by stanbon, solver91311:
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! If Jack tosses a game cartridge to Darnell with an initial velocity of 35 feet per second, an equation for the height h feet of the cartridge after t seconds is h=-16t^2+35t+5.
a. If the window is 25 feet above the ground, will Darnell have 0, 1, or 2 chances to catch the video game?
Solve: -16t^2+35t+5 = 25
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-16t^2 + 35t - 20 = 0
b^2 -4ac = 35^2 - 4(-17)(-20) = -135
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So there are no Real Number solutions.
Darnell will have 0 chances to catch the ball.
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b. If Darnell is unable to catch the video game, when will it hit the ground?
Solve -16t^2 + 35t + 5 = 0
t = 2.322 seconds
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Cheers,
Stan H.
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Answer by solver91311(24713)  (Show Source):
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