SOLUTION: The volume of a rectangular solid is 540 cubit feet. The width is 3 feet more than the height, and the lenght is 4 more feet than the height. Find the dimensions of the solid. w=h

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equation Customizable Word Problems -> SOLUTION: The volume of a rectangular solid is 540 cubit feet. The width is 3 feet more than the height, and the lenght is 4 more feet than the height. Find the dimensions of the solid. w=h      Log On


   



Question 695021: The volume of a rectangular solid is 540 cubit feet. The width is 3 feet more than the height, and the lenght is 4 more feet than the height. Find the dimensions of the solid.
w=h+3
l=h+4
h= ?
540=(h+3)*(h+4)*h
540=h^3+7h^2+12h
How to resolve ?

Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
540=h%5E3%2B7h%5E2%2B12h --> h%5E3%2B7h%5E2%2B12h-540=0
Any rational zero of the polynomial P%28h%29=h%5E3%2B7h%5E2%2B12h-540 will be a factor of 540, with a + or a - sign.
540=2%5E2%2A3%5E3%2A5
You know we are looking for a positive solution, so I would try + signs first.
The choices for factors are 1,2,3,4,5,6,9,10,12,15,18,20,27,30,36,45,54,60,90,108,135,180,270, and 540.
It is obvious that for positive h values, as h increases, P%28h%29 increases.
P%281%29=1%2B7%2B12-540%3C0 and P%2810%29=1000%2B700%2B120-540%3E0,
so the solution could be one of the factors in between 1 and 10: 2,3,4,5,6,and 9.
P%285%29=125%2B7%2A25%2B12%2A5-540=125%2B175%2B60-540=360-540=-180,
so we expect that the solution could be one of the factors between 5 and 10 (either 6 or 9).
P%286%29=216%2B7%2A36%2B12%2A6-540=216%2B252%2B72-540=0, so highlight%28h=6%29 is one solution.
Is there another solution?
Of course not.
If we make h smaller, the width and length will be smaller, and the volume will have to be smaller.
If we make h larger, the width and length will be larger, and the volume will have to be larger.