SOLUTION: What are the solutions go 4x^2+5=-67?

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Question 615944: What are the solutions go 4x^2+5=-67?
Found 2 solutions by JBarnum, jsmallt9:
Answer by JBarnum(2146) About Me  (Show Source):
You can put this solution on YOUR website!
4x%5E2%2B5=-67 subtract 5
4x%5E2=-72 divide by 4
x%5E2=-18 take the sqrt of each side
sqrt%28x%5E2%29=+sqrt%28-18%29
x=+3sqrt%28-2%29
when taking the square root of something it has a plus or minus before it
+3sqrt%28-2%29
-3sqrt%28-2%29

Answer by jsmallt9(3758) About Me  (Show Source):
You can put this solution on YOUR website!
4x%5E2%2B5=-67
Subtract 5 from each side:
4x%5E2=-72
Divide both sides by 4:
x%5E2=-18

Assuming you are not interested in complex solutions, then we stop here. You can't square something and get a negative number, as this equation says, unless you work with complex numbers.