SOLUTION: A catapult launches a boulder with an upward velocity of 148 ft/s. The height of the boulder (h) in feet after t seconds is given by the function h = –16t˛ + 148t + 30. How long do

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Question 556451: A catapult launches a boulder with an upward velocity of 148 ft/s. The height of the boulder (h) in feet after t seconds is given by the function h = –16t˛ + 148t + 30. How long does it take the boulder to reach its maximum height? What is the boulder’s maximum height? Round to the nearest hundredth, if necessary
Answer by nerdybill(7384) About Me  (Show Source):
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A catapult launches a boulder with an upward velocity of 148 ft/s. The height of the boulder (h) in feet after t seconds is given by the function h = –16t˛ + 148t + 30.
.
How long does it take the boulder to reach its maximum height?
h+=+-16t%5E2+%2B+148t+%2B+30
max height reached at vertex
t = -b/(2a)
t = -148/(2*(-16))
t = -148/(-32)
t = 4.625 seconds
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What is the boulder’s maximum height? Round to the nearest hundredth, if necessary
h+=+-16t%5E2+%2B+148t+%2B+30
set t to 4.625 and solve for h:
h+=+-16%284.625%29%5E2+%2B+148%284.625%29+%2B+30
h+=+372.25+ feet