SOLUTION: How can i find the vertex of Y=(x-4)^2 +5

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Question 555180: How can i find the vertex of

Y=(x-4)^2 +5
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
The vertex of y = a(x-h)^2+k is (h,k). In the case of y=(x-4)^2+5, we see that h=4 and k=5. So the vertex is (4,5)


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