SOLUTION: I am having a hard time on this equation. . . F(x)=1/5(x+2)^2+2 and was wondering if anyone could please help me? I need to find the vertex, line of symmetry and the maximum or min

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equation Customizable Word Problems -> SOLUTION: I am having a hard time on this equation. . . F(x)=1/5(x+2)^2+2 and was wondering if anyone could please help me? I need to find the vertex, line of symmetry and the maximum or min      Log On


   

Question 523145: I am having a hard time on this equation. . . F(x)=1/5(x+2)^2+2 and was wondering if anyone could please help me? I need to find the vertex, line of symmetry and the maximum or minimum value, once I can receive the correct answer for the vertex I can figure out the rest. Thank you in advance :)
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
the equation is in vertex form ___ y = a(x - h)^2 + k , (h,k) is the vertex