SOLUTION: solve this using the quadratic forumula: x^2-5x+1=0

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Question 490051: solve this using the quadratic forumula:
x^2-5x+1=0
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
a= 1 ,b= -5 ,c= 1

b^2-4ac= 25 + -4
b^2-4ac= 21
x=%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29
x1=%28-b%2Bsqrt%28b%5E2-4ac%29%29%2F%282a%29
x1=%28-12%2B21%29%2F%2812%29
x1=( 5 + 4.58 )/ 2
x1= 4.79
x2=( 5 -4.58 ) / 2
x2= 0.21