SOLUTION: We are trying to Factor the equation 2x^4 - 4x^3 + 8x^2. We factor out 2x^2 out. 2x^2(x^2 - 2x + 4) We then input into the quadratic equation (-(-2) +/- sqroot of -2^2 - 4(1)(4))
Question 487150: We are trying to Factor the equation 2x^4 - 4x^3 + 8x^2. We factor out 2x^2 out. 2x^2(x^2 - 2x + 4) We then input into the quadratic equation (-(-2) +/- sqroot of -2^2 - 4(1)(4)) / 2(1). That give us (2 +/- sqroot -12) / 2. should be able to reduce that to 1 +/- (sqroot 3)i. So now we need to understand how to write the answer. Would it be 2x^2(x - (1 + [sqroot 3]i)(x + (1 + [sqroot 3]i)?? Some how this just does not appear to me to be the correct answer.
Thanks
Glenn and James Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Factor the equation 2x^4 - 4x^3 + 8x^2
Let's see what I get here
2x^2(x^2 - 2x + 4)
first solution
2x^2 = 0
x = 0
:
Other solutions
x^2 - 2x + 4
using the complete the square method
x^2 - 2x + ____ = -4
complete the square
x^2 - 2x + 1 = -4 + 1
(x-1)^2 = -3
x - 1 = +/-
x - 1 = +/-
Two solutions
x = 1 +
x = 1 -
:
So we have x = 0, (1+) and (1-)
which is about what you had, except the 1st solution is x = 0 not 2x^2
