SOLUTION: A skin heals according to N(t)+N(o)e^-0.02t, where N is the number of square centimeters of unhealed skin t days after an injury, and N(o) is the number of square centimeter covere

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equation Customizable Word Problems -> SOLUTION: A skin heals according to N(t)+N(o)e^-0.02t, where N is the number of square centimeters of unhealed skin t days after an injury, and N(o) is the number of square centimeter covere      Log On


   

Question 47511: A skin heals according to N(t)+N(o)e^-0.02t, where N is the number of square centimeters of unhealed skin t days after an injury, and N(o) is the number of square centimeter covered by the original wound. How many days (to the nearest tenth ofa day) will it take for 50% of the wound to heal?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
N(t)=N(o)e^-0.02t How many days (to the nearest tenth ofa day) will it take for 50% of the wound to heal?
50% of N(o) = 0.5N(o)
0.5N(o) = N(o)e^(-0.02t)
0.5 = e^(-0.2t)
Take the natural log to get:
-0.2t=ln(0.5)
-0.2t=-0.6931...
t=3.5 days
Cheers,
Stan H.