SOLUTION: Determine the graph of the quadratic equation y = x2 + 4x – 1.

 

Hi,

Using the vertex form of a parabola,  where(h,k) is the vertex

y = x^2 + 4x – 1

f(x)= (x+2)^2 -4 - 1

f(x)= (x+2)^2 -5  V(-2,-5) minimum  a =1 a>0 Parabola opens upward

                    Line of symmetry x = -2