SOLUTION: how do i find A : B = tan A B is 2.667, but i dont know what the next step is. after I find A, im supposed to use it in the equation : a =[ -16 / v^2 (cos A)^2]x^2 + (tan A)x

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equation Customizable Word Problems -> SOLUTION: how do i find A : B = tan A B is 2.667, but i dont know what the next step is. after I find A, im supposed to use it in the equation : a =[ -16 / v^2 (cos A)^2]x^2 + (tan A)x      Log On


   



Question 430134: how do i find A :
B = tan A
B is 2.667, but i dont know what the next step is.
after I find A, im supposed to use it in the equation :
a =[ -16 / v^2 (cos A)^2]x^2 + (tan A)x
so any help would be appreciated

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
how do i find A :
B = tan A
B is 2.667, but i dont know what the next step is.
-------------
Use a calculator to find A
A =~ 69.446 degrees
----------------------
after I find A, im supposed to use it in the equation :
a =[ -16 / v^2 (cos A)^2]x^2 + (tan A)x
so any help would be appreciated
------------------
a =[ -16 / v^2 (cos A)^2]x^2 + (tan A)x
cos(A) =~ 0.351
tan(A) = b = 2.667
Sub for those. I don't know what v and x are.