SOLUTION: (x-1)(x+1)(x)=120

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Question 429922: (x-1)(x+1)(x)=120



















Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
(x-1)(x+1)(x)=120
x%5E3+-+x+-+120+=+0
x%5E3+-+x+=+120
x = 5
%28x-5%29%2A%28x%5E2+%2B+5x+%2B+24%29+=+0
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x%5E2+%2B+5x+%2B+24+=+0
Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation ax%5E2%2Bbx%2Bc=0 (in our case 1x%5E2%2B5x%2B24+=+0) has the following solutons:

x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca

For these solutions to exist, the discriminant b%5E2-4ac should not be a negative number.

First, we need to compute the discriminant b%5E2-4ac: b%5E2-4ac=%285%29%5E2-4%2A1%2A24=-71.

The discriminant -71 is less than zero. That means that there are no solutions among real numbers.

If you are a student of advanced school algebra and are aware about imaginary numbers, read on.


In the field of imaginary numbers, the square root of -71 is + or - sqrt%28+71%29+=+8.42614977317636.

The solution is , or
Here's your graph:
graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B5%2Ax%2B24+%29