SOLUTION: I am stuck on this word problem and greatly need assistance! Thank you
A garden area is 30 ft long and 20 ft wide. A path of uniform width is set around the edge. If the remainin
Question 42229This question is from textbook
: I am stuck on this word problem and greatly need assistance! Thank you
A garden area is 30 ft long and 20 ft wide. A path of uniform width is set around the edge. If the remaining garden area is 400ft^2, what is the width of the path?
1 solutions
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Answer 27356 by fractalier(1262) on 2006-06-15 10:15:39 (Show Source):
Well let the path have a width x.
Then the garden with the path will have a length 30 + 2x and a width 20 + 2x.
Since the new area is 400, we have
A = LW
400 = (30 + 2x)(20 + 2x)
400 = 600 + 60x + 40x + 4x^2
now rearrange and get
4x^2 + 100x + 200 = 0
x^2 + 25x + 50 = 0
this does not factor so we use the quadratic
x = (-25 ± sqrt(625-200)) / 2
x = (-25 ± sqrt(425)) / 2
there does not seem to be a solution that works...perhaps you need to rephrase the problem correctly...
Beginning Algebra, 6/e My initial request is exactly how the problem is worded. I am really stumped. This question is from textbook
