SOLUTION: Write a quadritic equation such that the sum of the roots is 6 and the product of the roots is -11.

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Question 41105: Write a quadritic equation such that the sum of the roots is 6 and the product of the roots is -11.
Answer by psbhowmick(878) About Me  (Show Source):
You can put this solution on YOUR website!
A general form of quadritic equation is: ax%5E2+%2B+bx+%2B+c+=+0 ______(1).
Let the roots of this equation be A and B.

[A quadritic equation has two roots. Try to prove this proposition.]

Then, sum of the roots: A+%2B+B+=+-b%2Fa
and product of the roots: A%2AB+=+c%2Fa

Thus in our case -b%2Fa+=+6 i.e. b = -6a
and c%2Fa+=+-11 i.e. c = -11a
Substituting these values of b & c in (1) we have
ax%5E2+%2B+%28-6a%29%2Ax+%2B+%28-11a%29+=+0
or ax%5E2+-+6ax+-+11a+=+0
or x%5E2+-+6x+-+11+=+0

Thus the reqd. equation is x%5E2+-+6x+-+11+=+0.