SOLUTION: Find for each trinomial the value of k which makes the trinomial a perfact square. x^2 - 6x + k

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Question 41102: Find for each trinomial the value of k which makes the trinomial a perfact square.

x^2 - 6x + k
Answer by fractalier(6550) About Me  (Show Source):
You can put this solution on YOUR website!
For x^2 - 6x + k,
the way we find k is to take 1/2 of -6 and then square it, so we have
[(1/2)(-6)]^2 =
(-3)^2 =
9