SOLUTION: i would like to know the vertex and the axis of symmetry and how to get both of these with work shown thanks.: 1/4(x+2)^2+6 and another equation: 2(x+2)(x+4)

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Question 410547: i would like to know the vertex and the axis of symmetry and how to get both of these with work shown thanks.:
1/4(x+2)^2+6 and another equation: 2(x+2)(x+4)
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi

Using the vertex form of a parabola, y=a%28x-h%29%5E2+%2Bk where(h,k) is the vertex

 y = 1/4(x+2)^2+6   |Vertex is Pt(-2,6), Axis of symmetry is x = -2



 y = 2(x+2)(x+4)

 y = 2(x^2 + 6x + 8)

 y = 2[(x+3)^2 - 9 + 8]

 y = 2(x+3)^2 - 2   |Vertex is Pt(-3,-2), Axis of symmetry is x = -3