SOLUTION: ^_^ fireboat salutes by shooting water into the air. How high does the middle stream if the water reach if water height is described by the function {{{h =20+76t-16t^2}}} ^_^ thks

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equation Customizable Word Problems -> SOLUTION: ^_^ fireboat salutes by shooting water into the air. How high does the middle stream if the water reach if water height is described by the function {{{h =20+76t-16t^2}}} ^_^ thks      Log On


   

Question 40922: ^_^ fireboat salutes by shooting water into the air. How high does the middle stream if the water reach if water height is described by the function h+=20%2B76t-16t%5E2 ^_^ thks
Answer by fractalier(6550) About Me  (Show Source):
You can put this solution on YOUR website!
The maximum height that the water reaches is just the maximum value of the function
h(t) = 20 + 76t - 16t^2
We can find that maximum height value by finding for what value of t it occurs and then plugging that into the function...like this...
For any f(x) = ax^2 + bx + c, the max occurs at -b/2a...in our function that is
-76/-32 = 19/8 sec
Now plug 19/8 in for t and get the height...
h(19/8) = 20 + 76(19/8) - 16(19/8)^2
h(19/8) = 110.25 (feet?) (meters?)