SOLUTION: some students planned for a get-together. The budget for food was $500.00 Five of the students failed to come because of the distance and therefore the cost of food for each memb
Question 40645This question is from textbook
: some students planned for a get-together. The budget for food was $500.00 Five of the students failed to come because of the distance and therefore the cost of food for each member increased by $5.00. How many students attended the get-together? This question is from textbook
You can put this solution on YOUR website! Let n be the students who attended
5 steudents were absent
total students = n+5
let x be the cost per student initially
then (n+5)*x = 500 ...eqn 1
after dinner..
number of students = n
cost per student = x+5
then n * (x+5) = 500 ...eqn 2
from eqn 2, we get n = 500/(x+5)..
substituting n = 500/(x+5)..in eqn 1
we get
((500/(x+5)+5)x = 500
(500+5x+25)/x+5) = 500/x
(500+5x+25)x = 500x+2500
5x^2 + 525x - 2500 = 0
x^2 + 5x - 500 = 0
x = 20
n+5 = 500/x = 500/20 = 25
n =25-5 =20.
okay
