Question 402723: The equation x^2 + k = 6 x has two distinct real roots. Find the range of values of k.
:) =)
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! The equation x^2 + k = 6 x has two distinct real roots. Find the range of values of k.
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Ans: 2 distict Real roots implies b^2-4ac > 0
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Rearrange the equation:
x^2-6x+k = 0
Solve:; 6^2-4*1*k > 0
36 -4k > 0
36 > 4k
k < 9
That is the range of the values of "k".
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Cheers,
Stan H.
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