SOLUTION: How do you solve this equation: 2(m+1)²=3m+7

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Question 399231: How do you solve this equation: 2(m+1)²=3m+7
Found 2 solutions by josmiceli, unlockmath:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
2%2A%28m%5E2+%2B+2m+%2B+1%29+=+3m+%2B+7
2m%5E2+%2B+4m+%2B+2+=+3m+%2B+7
2m%5E2+%2B+m+-+5+=+0
use quadratic formua:
m+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+%7D%7D%0D%0A%7B%7B%7Ba+=+2
b+=+1
c+=+-5
m+=+%28-1+%2B-+sqrt%28+1%5E2+-+4%2A2%2A%28-5%29+%29%29%2F%282%2A2%29+
m+=+%28-1+%2B-+sqrt%28+41+%29%29%2F4+

Answer by unlockmath(1688) About Me  (Show Source):
You can put this solution on YOUR website!
Hello,
First let's expand this 2(m+1)²=3m+7 to get:
2m^2+4m+2=3m+7
Subtract 3m+7 from both sides:
2m^2+m-5=0
To solve this we need to plug it into the quadratic formula:
x = -1 +- (sqrt 41)/4
There we go.
Make sense?
RJ
www.math-unlock.com