Question 3854: Im trying to do my homework, but I dont understand it.
It says y=x(squared)+1
and to find the
Y-intercept:
X-Intercept:
Vertex:
axus of symmetry:
Thanks.
Answer by longjonsilver(2297)   (Show Source):
You can put this solution on YOUR website! the y-intercept is where x=0, we then get y=1. Done!
the x-intercept(s) is/are where y=0, so we get  . Re-arranging, we get  , so x= +- . For this, you need to know Complex numbers. As far as you are concerned, there are no answers ie the curve does not cross the x-axis.
differentiate, to give dy/dx = 2x.
The turning point (vertex) is where the gradient (dy/dx) is zero, so ask this of th eequation: 2x=0 --> x=0. And y at this point?. It is y=1 (we already found the point earlier).
So, the vertex is at (0,1). The axis of symmetry always goes through the turning point, so axis is the y-axis, whose equation is x=0.
Just, so you can see it, here is the graph:
jon.
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