SOLUTION: Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function. f(x)=4x^2-8x+7
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-> SOLUTION: Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function. f(x)=4x^2-8x+7
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Question 379478
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Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function.
f(x)=4x^2-8x+7
Answer by
robertb(5830)
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. Vertex is the point (1,3). Line of symmetry is x = 1, and the minimum value is 3.