SOLUTION: The quadratic x2 + 20x + 100 has what type of roots?

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Question 377918: The quadratic x2 + 20x + 100 has what type of roots?

Found 3 solutions by richard1234, sophxmai, nyc_function:
Answer by richard1234(7193) About Me  (Show Source):
You can put this solution on YOUR website!
This factors to %28x%2B10%29%5E2, which has a double root x = -10.

Answer by sophxmai(62) About Me  (Show Source):
You can put this solution on YOUR website!
I'm assuming you're asking whether k>0, k=0, or k<0.

x2 + 20x + 100
Your equation for discriminant is b%5E2-4ac
So,
b%5E2-4ac
=%2820%29%5E2-4%281%29%28100%29
=400-400
=0

Since the discriminant is 0, k=0.
This means that the equation has one real root.

Answer by nyc_function(2741) About Me  (Show Source):
You can put this solution on YOUR website!
When we factor x^2 + 20x + 100, we get (x + 10)^2. Of course this means there are 2 factors of the same type.

Our two factors: (x + 10) and (x + 10).

If we set one of the factors to zero and solve for x, we get x = -10.

The root is negative as the answer for x is -10.

I hope this helps.