SOLUTION: the answers are -9 and 1, i am trying to understand this process, so x = -9 and x = 1, so x^2(x -9)(x 1) so x^2 + 3x -9 = 0 ??? i must be doing something wrong and i need help..

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equation Customizable Word Problems -> SOLUTION: the answers are -9 and 1, i am trying to understand this process, so x = -9 and x = 1, so x^2(x -9)(x 1) so x^2 + 3x -9 = 0 ??? i must be doing something wrong and i need help..      Log On


   



Question 377907: the answers are -9 and 1, i am trying to understand this process, so x = -9 and x = 1, so x^2(x -9)(x 1) so x^2 + 3x -9 = 0 ???
i must be doing something wrong and i need help...

Found 2 solutions by edjones, sophxmai:
Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
x = -9 and x = 1
(x+9)(x-1)
=x^2+8x-9 FOIL
.
Ed

Answer by sophxmai(62) About Me  (Show Source):
You can put this solution on YOUR website!
When x=-9, the binomial is actually x+9
This is because when you solve for x from x+9,
x+9=0
x+9-9=0-9
x=-9

Same thing with the x=1.
When x=1, the binomial is x-1
This is because when you solve for x from x-1,
x-1=0
x-1+1=0+1
x=1

Since your binomials are (x+9) and (x-1),
your equation is (x+9)(x-1)=0

(x+9)(x-1)=0
x%5E2-x%2B9x-9=0
x%5E2%2B8x-9=0