SOLUTION: determine what type of number the solutions are and how many solutions exist {{{ 10x^2-x-2=0 }}}

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Question 366982: determine what type of number the solutions are and how many solutions exist
+10x%5E2-x-2=0+
Found 2 solutions by robertb, stanbon:
Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
Evaluate the discriminant sqrt%28b%5E2-4ac%29+=+sqrt%28%28-1%29%5E2+-+4%2A10%2A%28-2%29%29+=+sqrt%2881%29+=+9%3E0, hence the roots are two distinct real numbers. Also note that +10x%5E2-x-2=%285x%2B2%29%282x-1%29+

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
10x^2-x-2=0
a = 10, b = -1, c = -2
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b^2-4ac = 100-4*10*-2 = 180
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Since b^2-4ac > 0 there are
2 Real Number solutions.
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Cheers,
Stan H.