SOLUTION: The width of a rectangle is 1 ft less than the length. the area is 2 ft^2. Find the length and the width.
Algebra
->
Quadratic Equations and Parabolas
->
Quadratic Equation Customizable Word Problems
-> SOLUTION: The width of a rectangle is 1 ft less than the length. the area is 2 ft^2. Find the length and the width.
Log On
Quadratics: solvers
Quadratics
Practice!
Practice
Answers archive
Answers
Lessons
Lessons
Word Problems
Word
In Depth
In
Click here to see ALL problems on Quadratic Equations
Question 363758
:
The width of a rectangle is 1 ft less than the length. the area is 2 ft^2. Find the length and the width.
Answer by
checkley77(12844)
(
Show Source
):
You can
put this solution on YOUR website!
W=L-1
WL=2
(L-1)L=2
L^2-L=2
L^2-L-2=0
(L-2)(L+1)=0
L-2=0
L=2 ANS. FOR THE LENGTH.
W=2-1=1 ANS. FOR THE LENGTH.
PROOF:
2*1=2
2=2