SOLUTION: a woodland jumping mouse hops along a parabolic path given by y=-0.2xsquared +1.3x where x is the mouses horazontal position(in feet) and y is the corasponding hight (in feet). can

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equation Customizable Word Problems -> SOLUTION: a woodland jumping mouse hops along a parabolic path given by y=-0.2xsquared +1.3x where x is the mouses horazontal position(in feet) and y is the corasponding hight (in feet). can      Log On


   



Question 363564: a woodland jumping mouse hops along a parabolic path given by y=-0.2xsquared +1.3x where x is the mouses horazontal position(in feet) and y is the corasponding hight (in feet). can the mouse jump over a fence that is 3 feet high? explain
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
a woodland jumping mouse hops along a parabolic path given by
y=-0.2xsquared +1.3x
where x is the mouse's horizontal position(in feet) and y is the corasponding height (in feet).
can the mouse jump over a fence that is 3 feet high? explain
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Maximum height occurs at x = -b/2a = -1.3/(2*-0.2) = 3.25 ft
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The mouse reaches maximum height at 3.25 ft from its starting point.
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Its height at that position is
f(3.25) = -0.2(3.25)^2+1.3(3.25) = 2.1125 ft
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Mousy cannot get over the fence.
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Cheers,
Stan H.