Question 361942: Solve
a^3+4s^2-45a=0
Answers
A) 0,-5,9
B) 5,-9
C) -36,-9
D)0,5,-9
ps ^ means to the power of ....thanks
Found 2 solutions by Theo, ewatrrr:
Answer by Theo(13342)   (Show Source):
You can put this solution on YOUR website! the formula is:
a^3 + 4a^2 - 45a = 0
factor out an a to get:
a * (a^2 + 4a - 45) = 0
factor the a^2 + 4a - 45 to get:
a * (a + 9) * (a - 5) = 0
your solutions are:
a = 0
a = -9
a = 5
you confirm by substituting in your equation to see if it is true.
your equation is
a^3 + 4a^2 - 45a = 0
when a = 0, the equation becomes 0 + 0 - 0 = 0 which becomes 0 = 0
when a = -9, the equation becomes -729 + 324 + 405 = -729 + 729 = 0
when a = 5, the equation becomes 125 + 100 - 225 = 225 - 225 = 0
answer is confirmed as good.
Answer by ewatrrr(24785)  (Show Source):
You can put this solution on YOUR website!
Hi
Assuming the s is an 'a'
a^3+4a^2-45a=0
solving
a(a^2 + 4a - 45) = 0
a(a + 9)(a - 5) = 0
a = 0
(a + 9)= 0
a = -9
(a - 5)= 0
a = 5
solutions are: 0, -9 and 5
answer d would be the correct choice
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