SOLUTION: 2x^2+7x-5 = x^2+6x+7

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Question 347025: 2x^2+7x-5 = x^2+6x+7
Answer by jsmallt9(3758) About Me  (Show Source):
You can put this solution on YOUR website!
2x%5E2%2B7x-5+=+x%5E2%2B6x%2B7
This is a quadratic equation. So we want one side e4qual to zero. I'll start by subtracting the entire right side of the equation from both sides:
2x%5E2%2B7x-5+-+%28x%5E2%2B6x%2B7%29+=+x%5E2%2B6x%2B7+-+%28x%5E2%2B6x%2B7%29
giving us:
x%5E2+%2B+x+-12+=+0
Now we factor (or use the Quadratic Formula). This factors pretty easily. The factors of -12 that add up to 1 are 4 and -3:
%28x%2B4%29%28x-3%29+=+0
From the Zero Product property we know that this (or any) product can be zero only if one (or more) of the factors is zero. So:
x+4 = 0 or x-3 = 0
Solving these we get:
x = -4 or x = 3
These are the solutions to your equation.