SOLUTION: Three consecutive even integers are such that the square of the third is 76 more than the square of the second. Find the three integers.

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Question 331018: Three consecutive even integers are such that the square of the third is 76 more than the square of the second. Find the three integers.
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
LET X, X+2 & X+4 BE THE THREE EVEN INTEGERS.
(X+4)^2=76+(X+2)^2
X^2+8X+16=76=X^2+4X+4
8X-4X=4+76-16
4X=64
X=64/4
X=16 ANS FOR THE SMALLEST INTEGER.
16=2=18 FOR THE MIDDLE INTYEGER.
16+4=20 FOR THE LARGEST INTEGER.
PROOF:
20^2=76+18^2
400=76+324
400=400