Question 262508: Use the discriminant to determine how many real number solutions the quadratic equation -4x^2 + 3x - 28 =0 has.
Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Use the discriminant to determine how many real number solutions the quadratic equation -4x^2 + 3x - 28 =0 has.
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a = -4 ; b = 3 ; c = -28
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b^2 - 4ac = 9 - 4*-4*-28 < 0
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Since the discriminant is < 0, the quadratic
has 2 unequal complex roots.
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Cheers,
Stan H.
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