SOLUTION: a rectangle is 8 feet long and 6 feet wide. if each dimension is increased by the same number of feet, a new rectangle is formed whose area exceeds the area if the original rectang

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equation Customizable Word Problems -> SOLUTION: a rectangle is 8 feet long and 6 feet wide. if each dimension is increased by the same number of feet, a new rectangle is formed whose area exceeds the area if the original rectang      Log On


   

Question 249378: a rectangle is 8 feet long and 6 feet wide. if each dimension is increased by the same number of feet, a new rectangle is formed whose area exceeds the area if the original rectangle by 72 square feet. find the dimensions of the new rectangle.
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
let a=area of rectangle with sides 8 ft and 6 ft
add x to each dimension
what is the formula for area of a rectangle?
formula=a
formula2=a+72=(8+x)(6+x)
what is a?
a=Length * width
substitute a below
a+72=(8+x)(6+x)
multiply out and find x