SOLUTION: Ok this is different to me, the question is in the formula of : 2/f+t=3/m, it says solve the equation for f(part 1 of the problem), then, calculate f from that formauls when

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equation Customizable Word Problems -> SOLUTION: Ok this is different to me, the question is in the formula of : 2/f+t=3/m, it says solve the equation for f(part 1 of the problem), then, calculate f from that formauls when       Log On


   

Question 23307: Ok this is different to me, the question is
in the formula of : 2/f+t=3/m,
it says solve the equation for f(part 1 of the problem),
then, calculate f from that formauls when
m=4, and t=3(part 2 of the problem).
PLease help
Found 2 solutions by stanbon, Earlsdon:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Multiply thru by "fm" to get rid of the fractions:
2m +ftm =3f
ftm=3f-2m
f = (3f-2m)/tm
If m=4 and t=3 the f=(3(3)-2(4))/((3)(4)
f= 1/12
Cheers,
Stan H.

Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
1) Solve for f:
%282%2Ff%29%2Bt=3%2Fm Subtract t from both sides of the equation.
2%2Ff+=+%283%2Fm%29-t Simplify the right side.
2%2Ff+=+%283-mt%29%2Fm Multiply both sides by f.
2+=+f%283-mt%29%2Fm Finally, multiply both sides by m%2F%283-mt%29
f+=+2m%2F%283-mt%29
2) Calculate f when m=4 and t=3
f+=+2%2A4%2F%283-4%2A3%29
f+=+8%2F%283-12%29
f+=+8%2F-9
f+=+-8%2F9