SOLUTION: Of the 1260 households in a small town, 632 have dogs, 568 have cats, and 114 have both types of pets. If a household is chosen at random, what is the probability that the househol
Question 22470: Of the 1260 households in a small town, 632 have dogs, 568 have cats, and 114 have both types of pets. If a household is chosen at random, what is the probability that the household has either type of pet? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! P(A or B) = P(A) + P(B) - P (A and B)
P(cats or dogs) = P(cats) + P(dogs) - P(cats and dogs)
= 586/1260 + 632/1260 - 114/1260
Cheers,
Stan H.