Question 205752: How to graph this equation: y=a(x-h)squared?
Answer by RAY100(1637)   (Show Source):
You can put this solution on YOUR website! the basic form of a parabola is,,,,,(y-k) =A(x-h)^2
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in this case, h=h,,k=0,,,,vertex is (h,k) or (h,0)
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parabola is a y parabola pointed up,,,,as A is positive
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A defines how wide the parabola is....
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also,,,basic form is ,,,(x-h)^2 = 4py,,,,with (0,p) as focus
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in this case (x-h)^2 = y/a,,,,or 4p = 1/a,,,or p=1/(4a)
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directrix is at y=-p,,,,,from basic info,,, or directrix is at y= -1/(4a)
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If numbers are available for h or a,,,,plot a few points to add definition
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