SOLUTION: This is a word problem and I can't use the perfect square I have to use the quadratic equation
5x7 photo that I have to put on a piece of paper
the area of the mat should equal t
Question 201718This question is from textbook
: This is a word problem and I can't use the perfect square I have to use the quadratic equation
5x7 photo that I have to put on a piece of paper
the area of the mat should equal that of the picture. I have to determine the proper l and width.
5x7 = 35 sp"
(5 + 2x)(7+2x) = 35
answer: l = 10.33 w = 9.33
but it's wrong that is larger than the photo This question is from textbook
You can put this solution on YOUR website! This is a word problem and I can't use the perfect square I have to use the quadratic equation
5x7 photo that I have to put on a piece of paper
the area of the mat should equal that of the picture. I have to determine the proper l and width.
5x7 = 35 sp"
(5 + 2x)(7+2x) = 35
Actually, the total area of the paper has to be 70 sq inches, since 35 will be covered by the photo.
(2x+5)*(2x+7) = 70
4x^2 + 24x - 35 = 0
x = 1.213 inches
You can put this solution on YOUR website! you have a 5x7 photo.
that would be 35 square inches.
you want the area of the mat that is showing after the picture is layed on it to be equal to the area of the photo.
your part of the mat that is showing must be 35 square inches.
what you need to do is get a mat that has an area of 70 square inches.
the area of the mat minus the area of the photo must equal 35 square inches.
so 70 - 35 = 35 square inches.
the mat will be bigger than the photo but the part of the mat that is showing will have an area of 35 square inches.
the photo will lay on the center of the mat covering 35 square inches.
another assumption is that the measurements of the mat should be in proportion to the measurements of the photo. this means that you want the mat to have the same ratio of length to width as the original photo.
your formula would be x * 35 = 70.
for this equation to be true, x must = 2.
the area of the mat should be 70 square inches.
the area of the photo is 35 square inches.
you lay the photo on the center of the mat and you leave 35 square inches exposed.
your original measurements for the photo are (5x7).
the ratio of length to width on the original photo is 7/5 = 1.4
you want a new length and a new width with the same ratio.
let l = new length
let w = new width.
your new length = 1.4 times the new width = 1.4*w.
so, your new length is 1.4*w and your new width is w.
your new area is 70 square inches.
length * width = area
w * 1.4w = 70
1.4*w^2 = 70
w^2 = 70/1.4
w = square root (70/1.4)
that would equal 7.071067812
so your new width is equal to that and your new length is equal to 1.4 times that equals 1.4 * 7.071067812 = 9.899494937.
your new area should be 70 square inches if this is correct.
length * width = 7.071067812 * 9.899494937 = 70 square inches.
this is ok and what it should be.
you will find that the amount of width exposed will be a total of 7.071067812 minus 5 inches, and that the amount of length exposed will be a total of 9.899494937 minus 7 inches. these will be distributed half on each end of the photo.
