SOLUTION: 2x^2-3x+2a=0 the 2a is giving me trouble

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Question 193074: 2x^2-3x+2a=0 the 2a is giving me trouble
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
I'm assuming that you want to solve for "x" right?



x+=+%28-b+%2B-+sqrt%28+b%5E2-4ac+%29%29%2F%282a%29 Start with the quadratic formula


x+=+%28-%28-3%29+%2B-+sqrt%28+%28-3%29%5E2-4%282%29%282a%29+%29%29%2F%282%282%29%29 Plug in a=2, b=-3, and c=2a. Note: there are two different "a" terms here...


x+=+%283+%2B-+sqrt%28+%28-3%29%5E2-4%282%29%282a%29+%29%29%2F%282%282%29%29 Negate -3 to get 3.


x+=+%283+%2B-+sqrt%28+9-4%282%29%282a%29+%29%29%2F%282%282%29%29 Square -3 to get 9.


x+=+%283+%2B-+sqrt%28+9-16a+%29%29%2F%282%282%29%29 Multiply 4%282%29%282a%29 to get 16a


x+=+%283+%2B-+sqrt%28+9-16a+%29%29%2F%284%29 Multiply 2 and 2 to get 4


x+=+%283+%2B+sqrt%28+9-16a+%29%29%2F4 or x+=+%283+-+sqrt%28+9-16a+%29%29%2F4 Break up the "plus/minus" to form two equations.


So the solutions are x+=+%283+%2B+sqrt%28+9-16a+%29%29%2F4 or x+=+%283+-+sqrt%28+9-16a+%29%29%2F4


If we knew the value of "a", then we could continue simplifying.