SOLUTION: 2y^ 2 -6y= 3
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Question 186994
:
2y^ 2 -6y= 3
Answer by
stanbon(75887)
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2y^ 2 -6y= 3
2y^2 -6y -3 = 0
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Use quadratic equation:
y = [6 +- sqrt(36 - 4*2*-3)]/4
y = [6 +- sqrt(60)]/4
y = [6 +- 2sqrt(15)]/4
y = [3 +- sqrt(15)]/2
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Cheers,
Stan H.