SOLUTION: Please help with this story problem. The number of tickets sold each day for a concert is N(x)=-0.3x^2+6x+10 where x is the number of days since the concert has been announced. W

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equation Customizable Word Problems -> SOLUTION: Please help with this story problem. The number of tickets sold each day for a concert is N(x)=-0.3x^2+6x+10 where x is the number of days since the concert has been announced. W      Log On


   



Question 176979: Please help with this story problem.
The number of tickets sold each day for a concert is N(x)=-0.3x^2+6x+10 where x is the number of days since the concert has been announced. When will sales peak and how many tickets will be sold that day?
Thank you

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
The number of tickets sold each day for a concert is N(x)=-0.3x^2+6x+10 where x is the number of days since the concert has been announced. When will sales peak and how many tickets will be sold that day?
:
N(x)=-0.3x^2+6x+10 is a quadratic equation so the max will occur at the axis of symmetry
The formula for that: x = %28-b%29%2F2%28a%29
In this equation, a=-.3, b=6
x = %28-6%29%2F2%28-.3%29
x = %28-6%29%2F%28-.6%29
x = +10 days when max tickets will be sold
;
"how many tickets will be sold that day?"
substitute 10 for x in the original equation:
N(x)=-0.3x^2+6x+10
N(x)=-0.3(10^2) + 6(10) + 10
N(x)=-30 + 60 + 10
N(x)= 40 tickets sold on day 10 which is the max
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did this make sense to you?