SOLUTION: Please help. Solve for the length and width. The length of a rectangle is twice the width. The area of the rectangle is 162yd^2. Find L and W. Thank you

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equation Customizable Word Problems -> SOLUTION: Please help. Solve for the length and width. The length of a rectangle is twice the width. The area of the rectangle is 162yd^2. Find L and W. Thank you       Log On


   

Question 176595: Please help. Solve for the length and width.
The length of a rectangle is twice the width. The area of the rectangle is 162yd^2. Find L and W.
Thank you
Answer by checkley75(3666) About Me  (Show Source):
You can put this solution on YOUR website!
L=2W
LW=162
2W*W=162
2W^2=162
W^2=162/2
W^2=81
W=SQRT81
W=9 ANS.
L=2*9=18 ANS.
pROOF:
9*18=162
162=162