SOLUTION: Can you PLEASE show me how to graph a quadratic function using its properties? f(x)=x^2-4x-5

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Question 171206: Can you PLEASE show me how to graph a quadratic function using its properties?
f(x)=x^2-4x-5

Answer by jojo14344(1513) About Me  (Show Source):
You can put this solution on YOUR website!
f%28x%29=x%5E2-4x-5+ ---> ax%5E2%2Bbx%2Bc=0
Okay, first we go for the Vertex-form of quadratic: f%28x%29=a%28x-h%29%5E2%2Bk
where, h & k are x%2Cy points on the vertex.
We'll do this by completing the square: We take 1%2F2 of "b" in the quadratic eq'n. and squared it. In this case it, "b"=4, so half of it --> %281%2F2%29%284%29=2, then squared, 2%5E2=highlight%284%29.
So we need to add "4" to the eqn:
.
f%28x%29=%28x%5E2-4x%2B4%29highlight%28-4%29-5 ----> remember to subtract 4 too so the expression does not change.
f%28x%29=%28x-2%29%5E2-9 ----> follows our vertex form now, where h=2 & k=-9. We'll see in the graph:
----> see points (2,-9). This will be the vertex.
Now we'll see the x-intercepts by solving the eqn:
x%5E2-4x-5=0
By Quadratic Formula, where ---->system%28a=1%2Cb=-4%2Cc=-5%29
x=%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29
x=%28-%28-4%29%2B-sqrt%28-4%5E2-4%2A1%2A-5%29%29%2F%282%2A1%29
x=%284%2B-sqrt%2816%2B20%29%29%2F2=%284%2B-sqrt%2836%29%29%2F2=%284%2B-6%29%2F2
x=%284%2B6%29%2F2=10%2F2=highlight%285%29
x=%284-6%29%2F2=-2%2F2=highlight%28-1%29
X-intercepts---->system%28x=5%2Cx=-1%29
See the graph again:

.
Thank you,
Jojo