SOLUTION: The length of a standard jewel case is 2cm more than it's width . The are of the rectangular top of the case is 168 cm squared . Find the length and width of the jewel case.

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equation Customizable Word Problems -> SOLUTION: The length of a standard jewel case is 2cm more than it's width . The are of the rectangular top of the case is 168 cm squared . Find the length and width of the jewel case.      Log On


   

Question 162534This question is from textbook Biginning Algebra
: The length of a standard jewel case is 2cm more than it's width . The are of the rectangular top of the case is 168 cm squared . Find the length and width of the jewel case. This question is from textbook Biginning Algebra

Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
L=W+2
AREA=L*W
168=(W+2)W
168=W^2+2W
W^2+2W-168=0
(W-12)(X+14)=0
W-12=0
W=12 IS THE WIDTH.
L=12+2=14 IS THE LENGTH.
PROOF:
168=12*14
168=168