Question 161416: The width of a rectangular gate is 2 meters
(m) larger than its height. The diagonal brace measures
sq root6 m. Find the width and height. Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website! X^2+(X+2)^2=(SQRT6)^2
X^2+X^2+4X+4=6
2X^2+4X+4-6=0
2X^2+4X-2=0
2(X^2+2X-1)=0
X=(-2+-SQRT[2^2-4*1*-1])/2*1
X=(-2+-SQRT4+4])/2
X=(-2+-SQRT8)/2
X=(-2+-2.828)/2
X=(-2+2.828)/2
X=.828/2
X=.414 ANSWER.
X=(-2-2.828)/2
X=-4.828/2
X=-2.414 ANSWER.