SOLUTION: 3x^3-24 Since 24 is not a perfect cube I think I factor out the 3 as follows: 3(x^3-8) Am I on the right track?

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equation Customizable Word Problems -> SOLUTION: 3x^3-24 Since 24 is not a perfect cube I think I factor out the 3 as follows: 3(x^3-8) Am I on the right track?      Log On


   

Question 156799: 3x^3-24
Since 24 is not a perfect cube I think I factor out the 3 as follows:
3(x^3-8)
Am I on the right track?
Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
Yes.
.
After pulling out the 3, the remainder is a "difference of cubes" -- now, you can apply "special factoring".
.
See:
http://www.purplemath.com/modules/specfact2.htm
for detailed information
.
3(x^3-8)
3(x-2)(x^2 + 2x + 2^2)
3(x-2)(x^2 + 2x + 4)