SOLUTION: for the derivative value I need to show tongant line in graph? Thanks Given y=X^2 at x = -2 So far I have At X=-2, the derivative is 2(-2)= 0 (please show graph).

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equation Customizable Word Problems -> SOLUTION: for the derivative value I need to show tongant line in graph? Thanks Given y=X^2 at x = -2 So far I have At X=-2, the derivative is 2(-2)= 0 (please show graph).      Log On


   

Question 140475: for the derivative value I need to show tongant line in graph? Thanks
Given y=X^2
at x = -2
So far I have
At X=-2, the derivative is 2(-2)= 0 (please show graph).
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
f(x)=x^2
dy/dx = 2x
f'(-2) = -4 (slope of y=x^2 at (-2,4)
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Equation of line with m=-4 passing thru (-2,4)
4 = -2*-4 + b
b = -4
----------
EQUATION:
y = -4x -4
graph%28400%2C300%2C-10%2C10%2C-10%2C10%2Cx%5E2%2C-4x-4%29
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Cheers,
Stan H.