SOLUTION: x^2+4x+1=0

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Question 140241: x^2+4x+1=0
Answer by checkley77(12844) About Me  (Show Source):
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x^2+4x+1=0
Using the uadratic equation:x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29we get:
x=(-4+-sqrt4^2-4*1*1])/2*1
x=(-4+-sqrt[16-4])/2
x=(-4+-sqrt12)/2
x=(-4+-3.464)/2
x=(-4+3.464)/2
x=-.536/2
x=-.268 answer.
x=(-4-3.464)/2
x=-7.464/2
x=-3.732 answer.