SOLUTION: Once again, I am in need of your help. I am stuck on a quadratic equation that I have to graph... and out of 16 problems on this worksheet, this is the only one I have not been abl
Question 136457: Once again, I am in need of your help. I am stuck on a quadratic equation that I have to graph... and out of 16 problems on this worksheet, this is the only one I have not been able to solve. This is not from my book, this is off of a worksheet.
This is what I have so far:
y= x^2 + 2
a=1 b=0 c=2
a=1 > 0 parabola opens upwards
x=0
y=0^2 + 2
y-intercept is (0,2)
y=0 0=x^2 +2
x= -0±√(0^2-4(1)(2)
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2(-1)
x= 0±√(0-8)
-----------------
2
X=0 and this is where I am stuck at. I am sorry your page is not allowing me to use the proper quadratic equation form. I did the best that I could.
Would you please help me work through this? Thanks!! ~Lynn
You can put this solution on YOUR website! Your work so far is good!
But the x-intercepts are not right. Let y = 0. subtract 2 from both sides. Take the square root of both sides. and or... and
As you can see, the x-intercepts are not real, meaning the parabola does not cross the x-axis.
Here's the graph of the equation:
(