SOLUTION: A cup of tea cools exponentially according to the function T(x)=60(0.79)(^x/3)+30,where T is the temperature in degrees celcius and x is time in minutes. What was the initial tempe

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equation Customizable Word Problems -> SOLUTION: A cup of tea cools exponentially according to the function T(x)=60(0.79)(^x/3)+30,where T is the temperature in degrees celcius and x is time in minutes. What was the initial tempe      Log On


   

Question 126689: A cup of tea cools exponentially according to the function T(x)=60(0.79)(^x/3)+30,where T is the temperature in degrees celcius and x is time in minutes. What was the initial temperature of the tea? I think it is 90 degrees celcius. Can someone kindly confirm ???
Answer by kev82(151) About Me  (Show Source):
You can put this solution on YOUR website!
The initial temperature is when time (x) equals zero. Let's just check I read your equation right, did you mean:



In that case the answer is 60+30=90, yes.