Question 123806: Determine the maximum or minimum value of the quadratic function.
f(x)=x^2-6x+2 Found 2 solutions by stanbon, rapaljer:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Determine the maximum or minimum value of the quadratic function.
f(x)=x^2-6x+2
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max or min occurs at x = -b/2a = 6/2 = 3
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f(3) = 3^2-6*3+2 = -7
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minimum at (3,-7)
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Cheers,
Stan H.
You can put this solution on YOUR website! You can do this algebraically or graphically. What is your choice? I think the easiest way is graphical.
It looks like the minimum value of f(x) is y=-7.
Try algebraically to confirm this answer:
y=x^2-6x+2
There are several ways, probably the easiest of which is to find , where a is the coefficient of x^2 and b is the coefficient of x. Therefore, a=1, b=-6, so
(