SOLUTION: A rectangular parking lot has dimensions 16 metres by 40 metres. The total area of the parking lot is increased by 512 square metres by paving an extra strip of uniform width aroun

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equation Customizable Word Problems -> SOLUTION: A rectangular parking lot has dimensions 16 metres by 40 metres. The total area of the parking lot is increased by 512 square metres by paving an extra strip of uniform width aroun      Log On


   



Question 123263: A rectangular parking lot has dimensions 16 metres by 40 metres. The total area of the parking lot is increased by 512 square metres by paving an extra strip of uniform width around the entire lot. How wide is the strip?
Answer by solver91311(24713) About Me  (Show Source):
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Discussion



The key thing to remember in this problem is that the width of the added strip
is uniform, meaning it is the same width all the way around, and that the
overall length and overall width of the parking lot has been increased by 2
times this width.





Solution





Let x = the width of the uniform strip. Then the new width of the parking lot
is 16%2B2x meters and the new length of the parking lot is 40%2B2x meters.

So the overall area of the new larger parking lot is A%5Bn%5D=%2816%2B2x%29%2840%2B2x%29

But this area is 512m%5E2 larger than the area of the old parking lot which
was 16%2A40=640m%5E2.

Therefore we can write: A%5Bn%5D=%2816%2B2x%29%2840%2B2x%29=512%2B640=1152m%5E2

Multiply the binomials and collect like terms:
640%2B32x%2B80x%2B4x%5E2=1152
640-1152%2B112x%2B4x%5E2=0
-512%2B112x%2B4x%5E2=0

Divide by 4 and put in standard form:
x%5E2%2B28x-128=0

Factor:
-4+%2A+32+=+-128
-4+%2B+32+=+28

%28x-4%29%28x%2B32%29=0

So x=4 or x=-32

Since we are looking for a positive length, we can exclude the negative root.
The width of the strip around the old parking lot is 4 metres.





Check Answer



%2816%2B2%284%29%29%2840%2B2%284%29%29=24%2A48=1152=640%2B512=%2816%2A40%29%2B512 Checks.